-9(z+1)+4(4z-4)=6(z-4)+10

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Solution for -9(z+1)+4(4z-4)=6(z-4)+10 equation:



-9(z+1)+4(4z-4)=6(z-4)+10
We move all terms to the left:
-9(z+1)+4(4z-4)-(6(z-4)+10)=0
We multiply parentheses
-9z+16z-(6(z-4)+10)-9-16=0
We calculate terms in parentheses: -(6(z-4)+10), so:
6(z-4)+10
We multiply parentheses
6z-24+10
We add all the numbers together, and all the variables
6z-14
Back to the equation:
-(6z-14)
We add all the numbers together, and all the variables
7z-(6z-14)-25=0
We get rid of parentheses
7z-6z+14-25=0
We add all the numbers together, and all the variables
z-11=0
We move all terms containing z to the left, all other terms to the right
z=11

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