-9+(4z-2)=-(5z-5)+1

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Solution for -9+(4z-2)=-(5z-5)+1 equation: 



-9+(4z-2)=-(5z-5)+1

We move all terms to the left:

-9+(4z-2)-(-(5z-5)+1)=0

We get rid of parentheses

4z-(-(5z-5)+1)-2-9=0



We calculate terms in parentheses: -(-(5z-5)+1), so:

-(5z-5)+1

We get rid of parentheses

-5z+5+1

We add all the numbers together, and all the variables

-5z+6

Back to the equation:

-(-5z+6)



We add all the numbers together, and all the variables

4z-(-5z+6)-11=0

We get rid of parentheses

4z+5z-6-11=0

We add all the numbers together, and all the variables

9z-17=0

We move all terms containing z to the left, all other terms to the right

9z=17

z=17/9

z=1+8/9

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