-9+3(b+4)=3(1+b)

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Solution for -9+3(b+4)=3(1+b) equation:



-9+3(b+4)=3(1+b)
We move all terms to the left:
-9+3(b+4)-(3(1+b))=0
We add all the numbers together, and all the variables
3(b+4)-(3(b+1))-9=0
We multiply parentheses
3b-(3(b+1))+12-9=0
We calculate terms in parentheses: -(3(b+1)), so:
3(b+1)
We multiply parentheses
3b+3
Back to the equation:
-(3b+3)
We add all the numbers together, and all the variables
3b-(3b+3)+3=0
We get rid of parentheses
3b-3b-3+3=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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