-9+4b=3(b+4)-6b

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Solution for -9+4b=3(b+4)-6b equation: 



-9+4b=3(b+4)-6b

We move all terms to the left:

-9+4b-(3(b+4)-6b)=0



We calculate terms in parentheses: -(3(b+4)-6b), so:

3(b+4)-6b

We add all the numbers together, and all the variables

-6b+3(b+4)

We multiply parentheses

-6b+3b+12

We add all the numbers together, and all the variables

-3b+12

Back to the equation:

-(-3b+12)



We get rid of parentheses

4b+3b-12-9=0

We add all the numbers together, and all the variables

7b-21=0

We move all terms containing b to the left, all other terms to the right

7b=21

b=21/7

b=3

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