-9/(h+1)=2/(h-10)

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Solution for -9/(h+1)=2/(h-10) equation: 



-9/(h+1)=2/(h-10)

We move all terms to the left:

-9/(h+1)-(2/(h-10))=0



Domain of the equation: (h+1)!=0

We move all terms containing h to the left, all other terms to the right

h!=-1

h∈R





Domain of the equation: (h-10))!=0

h∈R



We calculate fractions


(-9h)/((h+1)*(h-10)))+(-(2*(h+1))/((h+1)*(h-10)))=0



We calculate terms in parentheses: -(2*(h+1))/((h+1)*(h-10))), so:

2*(h+1))/((h+1)*(h-10))

We multiply all the terms by the denominator


2*(h+1))

We multiply parentheses

2h+

We add all the numbers together, and all the variables

2h

Back to the equation:

-(2h)



We add all the numbers together, and all the variables

-2h+(-9h)/((h+1)*(h-10)))+(=0

We multiply all the terms by the denominator


-2h*((h+1)*(h-10)))+(+(-9h)=0

We get rid of parentheses

-2h*((h+1)*(h-10)))+(-9h=0

We add all the numbers together, and all the variables

-9h-2h*((h+1)*(h-10)))+(=0

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