-9/4v+4/5=7/8v=

Solution for -9/4v+4/5=7/8v= equation:

-9/4v+4/5=7/8v=

We move all terms to the left:

-9/4v+4/5-(7/8v)=0


Domain of the equation: 4v!=0

v!=0/4

v!=0

v∈R



Domain of the equation: 8v)!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

-9/4v-(+7/8v)+4/5=0

We get rid of parentheses

-9/4v-7/8v+4/5=0

We calculate fractions


1024v^2/800v^2+(-1800v)/800v^2+(-700v)/800v^2=0

We multiply all the terms by the denominator


1024v^2+(-1800v)+(-700v)=0

We get rid of parentheses

1024v^2-1800v-700v=0

We add all the numbers together, and all the variables

1024v^2-2500v=0

a = 1024; b = -2500; c = 0;
Δ = b2-4ac
Δ = -25002-4·1024·0
Δ = 6250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6250000}=2500$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2500)-2500}{2*1024}=\frac{0}{2048}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2500)+2500}{2*1024}=\frac{5000}{2048}
=2+113/256
$