-9/s=3

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Solution for -9/s=3 equation: 


D( s )

s = 0

s = 0

s = 0

s in (-oo:0) U (0:+oo)

-9/s = 3 // - 3

-9/s-3 = 0

-9*s^-1 = 3 // : -9

s^-1 = -1/3

-1 < 0

1/(s^1) = -1/3 // * s^1

1 = -1/3*s^1 // : -1/3

-3 = s^1

s = -3

s = -3

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