-90=12(1z-3)+6z

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Solution for -90=12(1z-3)+6z equation: 



-90=12(1z-3)+6z

We move all terms to the left:

-90-(12(1z-3)+6z)=0

We add all the numbers together, and all the variables

-(12(z-3)+6z)-90=0



We calculate terms in parentheses: -(12(z-3)+6z), so:

12(z-3)+6z

We add all the numbers together, and all the variables

6z+12(z-3)

We multiply parentheses

6z+12z-36

We add all the numbers together, and all the variables

18z-36

Back to the equation:

-(18z-36)



We get rid of parentheses

-18z+36-90=0

We add all the numbers together, and all the variables

-18z-54=0

We move all terms containing z to the left, all other terms to the right

-18z=54

z=54/-18

z=-3

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