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-94=-n(5n+7)
We move all terms to the left:
-94-(-n(5n+7))=0
We calculate terms in parentheses: -(-n(5n+7)), so:We get rid of parentheses
-n(5n+7)
We multiply parentheses
-5n^2-7n
Back to the equation:
-(-5n^2-7n)
5n^2+7n-94=0
a = 5; b = 7; c = -94;
Δ = b2-4ac
Δ = 72-4·5·(-94)
Δ = 1929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1929}}{2*5}=\frac{-7-\sqrt{1929}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1929}}{2*5}=\frac{-7+\sqrt{1929}}{10} $
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