-99=3x-4(4x+41)

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Solution for -99=3x-4(4x+41) equation: 



-99=3x-4(4x+41)

We move all terms to the left:

-99-(3x-4(4x+41))=0



We calculate terms in parentheses: -(3x-4(4x+41)), so:

3x-4(4x+41)

We multiply parentheses

3x-16x-164

We add all the numbers together, and all the variables

-13x-164

Back to the equation:

-(-13x-164)



We get rid of parentheses

13x+164-99=0

We add all the numbers together, and all the variables

13x+65=0

We move all terms containing x to the left, all other terms to the right

13x=-65

x=-65/13

x=-5

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