-9b(3b+1)+(28b-7)=0

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Solution for -9b(3b+1)+(28b-7)=0 equation: 



-9b(3b+1)+(28b-7)=0

We multiply parentheses

-27b^2-9b+(28b-7)=0

We get rid of parentheses

-27b^2-9b+28b-7=0

We add all the numbers together, and all the variables

-27b^2+19b-7=0

a = -27; b = 19; c = -7;
Δ = b2-4ac
Δ = 192-4·(-27)·(-7)
Δ = -395
Delta is less than zero, so there is no solution for the equation

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