-9c-50=-3(4+-4c)+-2c

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Solution for -9c-50=-3(4+-4c)+-2c equation: 



-9c-50=-3(4+-4c)+-2c

We move all terms to the left:

-9c-50-(-3(4+-4c)+-2c)=0

We add all the numbers together, and all the variables

-9c-(-3(-4c)+-2c)-50=0

We use the square of the difference formula

-9c-(-3(-4c)-2c)-50=0



We calculate terms in parentheses: -(-3(-4c)-2c), so:

-3(-4c)-2c

We add all the numbers together, and all the variables

-2c-3(-4c)

We multiply parentheses

-2c+12c

We add all the numbers together, and all the variables

10c

Back to the equation:

-(10c)



We add all the numbers together, and all the variables

-19c-50=0

We move all terms containing c to the left, all other terms to the right

-19c=50

c=50/-19

c=-2+12/19

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