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-9m(m-10)=0
We multiply parentheses
-9m^2+90m=0
a = -9; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·(-9)·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*-9}=\frac{-180}{-18} =+10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*-9}=\frac{0}{-18} =0 $
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