-9p-5(3-3p)=4(p-2)-13

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Solution for -9p-5(3-3p)=4(p-2)-13 equation:



-9p-5(3-3p)=4(p-2)-13
We move all terms to the left:
-9p-5(3-3p)-(4(p-2)-13)=0
We add all the numbers together, and all the variables
-9p-5(-3p+3)-(4(p-2)-13)=0
We multiply parentheses
-9p+15p-(4(p-2)-13)-15=0
We calculate terms in parentheses: -(4(p-2)-13), so:
4(p-2)-13
We multiply parentheses
4p-8-13
We add all the numbers together, and all the variables
4p-21
Back to the equation:
-(4p-21)
We add all the numbers together, and all the variables
6p-(4p-21)-15=0
We get rid of parentheses
6p-4p+21-15=0
We add all the numbers together, and all the variables
2p+6=0
We move all terms containing p to the left, all other terms to the right
2p=-6
p=-6/2
p=-3

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