-9v2+6v+3=4

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Solution for -9v2+6v+3=4 equation: 



-9v^2+6v+3=4

We move all terms to the left:

-9v^2+6v+3-(4)=0

We add all the numbers together, and all the variables

-9v^2+6v-1=0

a = -9; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-9)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-6}{-18}=1/3$

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