-9x(-3x-2)=-(x+3)

Solution for -9x(-3x-2)=-(x+3) equation:

-9x(-3x-2)=-(x+3)

We move all terms to the left:

-9x(-3x-2)-(-(x+3))=0

We multiply parentheses

27x^2+18x-(-(x+3))=0


We calculate terms in parentheses: -(-(x+3)), so:

-(x+3)

We get rid of parentheses

-x-3

We add all the numbers together, and all the variables

-1x-3

Back to the equation:

-(-1x-3)


We get rid of parentheses

27x^2+18x+1x+3=0

We add all the numbers together, and all the variables

27x^2+19x+3=0

a = 27; b = 19; c = +3;
Δ = b2-4ac
Δ = 192-4·27·3
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{37}}{2*27}=\frac{-19-\sqrt{37}}{54}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{37}}{2*27}=\frac{-19+\sqrt{37}}{54}
$