-9x(2x-1)+3(6x+5)=10(5x+16)-75

Solution for -9x(2x-1)+3(6x+5)=10(5x+16)-75 equation:

-9x(2x-1)+3(6x+5)=10(5x+16)-75

We move all terms to the left:

-9x(2x-1)+3(6x+5)-(10(5x+16)-75)=0

We multiply parentheses

-18x^2+9x+18x-(10(5x+16)-75)+15=0


We calculate terms in parentheses: -(10(5x+16)-75), so:

10(5x+16)-75

We multiply parentheses

50x+160-75

We add all the numbers together, and all the variables

50x+85

Back to the equation:

-(50x+85)


We add all the numbers together, and all the variables

-18x^2+27x-(50x+85)+15=0

We get rid of parentheses

-18x^2+27x-50x-85+15=0

We add all the numbers together, and all the variables

-18x^2-23x-70=0

a = -18; b = -23; c = -70;
Δ = b2-4ac
Δ = -232-4·(-18)·(-70)
Δ = -4511
Delta is less than zero, so there is no solution for the equation