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-9x-15=-2x(x+4)
We move all terms to the left:
-9x-15-(-2x(x+4))=0
We calculate terms in parentheses: -(-2x(x+4)), so:We get rid of parentheses
-2x(x+4)
We multiply parentheses
-2x^2-8x
Back to the equation:
-(-2x^2-8x)
2x^2+8x-9x-15=0
We add all the numbers together, and all the variables
2x^2-1x-15=0
a = 2; b = -1; c = -15;
Δ = b2-4ac
Δ = -12-4·2·(-15)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*2}=\frac{-10}{4} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*2}=\frac{12}{4} =3 $
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