-9y+3+2y=3(y-1)

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Solution for -9y+3+2y=3(y-1) equation: 



-9y+3+2y=3(y-1)

We move all terms to the left:

-9y+3+2y-(3(y-1))=0

We add all the numbers together, and all the variables

-7y-(3(y-1))+3=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

-7y-3y+3+3=0

We add all the numbers together, and all the variables

-10y+6=0

We move all terms containing y to the left, all other terms to the right

-10y=-6

y=-6/-10

y=3/5

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