-9y-(4+3y)=-(2y-1)-5

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Solution for -9y-(4+3y)=-(2y-1)-5 equation: 



-9y-(4+3y)=-(2y-1)-5

We move all terms to the left:

-9y-(4+3y)-(-(2y-1)-5)=0

We add all the numbers together, and all the variables

-9y-(3y+4)-(-(2y-1)-5)=0

We get rid of parentheses

-9y-3y-(-(2y-1)-5)-4=0



We calculate terms in parentheses: -(-(2y-1)-5), so:

-(2y-1)-5

We get rid of parentheses

-2y+1-5

We add all the numbers together, and all the variables

-2y-4

Back to the equation:

-(-2y-4)



We add all the numbers together, and all the variables

-12y-(-2y-4)-4=0

We get rid of parentheses

-12y+2y+4-4=0

We add all the numbers together, and all the variables

-10y=0

y=0/-10

y=0

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