-a+10-9/a=0

Solution for -a+10-9/a=0 equation:

-a+10-9/a=0


Domain of the equation: a!=0

a∈R


We add all the numbers together, and all the variables

-1a-9/a+10=0

We multiply all the terms by the denominator


-1a*a+10*a-9=0

We add all the numbers together, and all the variables

10a-1a*a-9=0

Wy multiply elements

-1a^2+10a-9=0

a = -1; b = 10; c = -9;
Δ = b2-4ac
Δ = 102-4·(-1)·(-9)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-8}{2*-1}=\frac{-18}{-2}
=+9
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+8}{2*-1}=\frac{-2}{-2}
=1
$