-b+b=3(b+2)-4b

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Solution for -b+b=3(b+2)-4b equation: 



-b+b=3(b+2)-4b

We move all terms to the left:

-b+b-(3(b+2)-4b)=0

We add all the numbers together, and all the variables

-(3(b+2)-4b)=0



We calculate terms in parentheses: -(3(b+2)-4b), so:

3(b+2)-4b

We add all the numbers together, and all the variables

-4b+3(b+2)

We multiply parentheses

-4b+3b+6

We add all the numbers together, and all the variables

-1b+6

Back to the equation:

-(-1b+6)



We get rid of parentheses

1b-6=0

We add all the numbers together, and all the variables

b-6=0

We move all terms containing b to the left, all other terms to the right

b=6

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