-b-(13+4b)=-3(5-9b)=2

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Solution for -b-(13+4b)=-3(5-9b)=2 equation: 



-b-(13+4b)=-3(5-9b)=2

We move all terms to the left:

-b-(13+4b)-(-3(5-9b))=0

We add all the numbers together, and all the variables

-b-(4b+13)-(-3(-9b+5))=0

We add all the numbers together, and all the variables

-1b-(4b+13)-(-3(-9b+5))=0

We get rid of parentheses

-1b-4b-(-3(-9b+5))-13=0



We calculate terms in parentheses: -(-3(-9b+5)), so:

-3(-9b+5)

We multiply parentheses

27b-15

Back to the equation:

-(27b-15)



We add all the numbers together, and all the variables

-5b-(27b-15)-13=0

We get rid of parentheses

-5b-27b+15-13=0

We add all the numbers together, and all the variables

-32b+2=0

We move all terms containing b to the left, all other terms to the right

-32b=-2

b=-2/-32

b=1/16

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