-c-12+3c=2(c-6)

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Solution for -c-12+3c=2(c-6) equation:


Simplifying
-1c + -12 + 3c = 2(c + -6)

Reorder the terms:
-12 + -1c + 3c = 2(c + -6)

Combine like terms: -1c + 3c = 2c
-12 + 2c = 2(c + -6)

Reorder the terms:
-12 + 2c = 2(-6 + c)
-12 + 2c = (-6 * 2 + c * 2)
-12 + 2c = (-12 + 2c)

Add '12' to each side of the equation.
-12 + 12 + 2c = -12 + 12 + 2c

Combine like terms: -12 + 12 = 0
0 + 2c = -12 + 12 + 2c
2c = -12 + 12 + 2c

Combine like terms: -12 + 12 = 0
2c = 0 + 2c
2c = 2c

Add '-2c' to each side of the equation.
2c + -2c = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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