-cos(2x)+2.98sin(x)+1=0

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Solution for -cos(2x)+2.98sin(x)+1=0 equation:


Simplifying
-1cos(2x) + 2.98sin(x) + 1 = 0

Remove parenthesis around (2x)
-1cos * 2x + 2.98sin(x) + 1 = 0

Reorder the terms for easier multiplication:
-1 * 2cos * x + 2.98sin(x) + 1 = 0

Multiply -1 * 2
-2cos * x + 2.98sin(x) + 1 = 0

Multiply cos * x
-2cosx + 2.98sin(x) + 1 = 0

Multiply ins * x
-2cosx + 2.98insx + 1 = 0

Reorder the terms:
1 + -2cosx + 2.98insx = 0

Solving
1 + -2cosx + 2.98insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2cosx + -1 + 2.98insx = 0 + -1

Reorder the terms:
1 + -1 + -2cosx + 2.98insx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2cosx + 2.98insx = 0 + -1
-2cosx + 2.98insx = 0 + -1

Combine like terms: 0 + -1 = -1
-2cosx + 2.98insx = -1

Add '-2.98insx' to each side of the equation.
-2cosx + 2.98insx + -2.98insx = -1 + -2.98insx

Combine like terms: 2.98insx + -2.98insx = 0.00
-2cosx + 0.00 = -1 + -2.98insx
-2cosx = -1 + -2.98insx

Divide each side by '-2osx'.
c = 0.5o-1s-1x-1 + 1.49ino-1

Simplifying
c = 0.5o-1s-1x-1 + 1.49ino-1

Reorder the terms:
c = 1.49ino-1 + 0.5o-1s-1x-1

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