-cos(x)+cos(2x)+cos(4x)=0

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Solution for -cos(x)+cos(2x)+cos(4x)=0 equation:


Simplifying
-1cos(x) + cos(2x) + cos(4x) = 0

Multiply cos * x
-1cosx + cos(2x) + cos(4x) = 0

Remove parenthesis around (2x)
-1cosx + cos * 2x + cos(4x) = 0

Reorder the terms for easier multiplication:
-1cosx + 2cos * x + cos(4x) = 0

Multiply cos * x
-1cosx + 2cosx + cos(4x) = 0

Remove parenthesis around (4x)
-1cosx + 2cosx + cos * 4x = 0

Reorder the terms for easier multiplication:
-1cosx + 2cosx + 4cos * x = 0

Multiply cos * x
-1cosx + 2cosx + 4cosx = 0

Combine like terms: -1cosx + 2cosx = 1cosx
1cosx + 4cosx = 0

Combine like terms: 1cosx + 4cosx = 5cosx
5cosx = 0

Solving
5cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '5'.
cosx = 0

Simplifying
cosx = 0

The solution to this equation could not be determined.

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