-g+2(2+g)=-4(g+1)

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Solution for -g+2(2+g)=-4(g+1) equation: 



-g+2(2+g)=-4(g+1)

We move all terms to the left:

-g+2(2+g)-(-4(g+1))=0

We add all the numbers together, and all the variables

-g+2(g+2)-(-4(g+1))=0

We add all the numbers together, and all the variables

-1g+2(g+2)-(-4(g+1))=0

We multiply parentheses

-1g+2g-(-4(g+1))+4=0



We calculate terms in parentheses: -(-4(g+1)), so:

-4(g+1)

We multiply parentheses

-4g-4

Back to the equation:

-(-4g-4)



We add all the numbers together, and all the variables

g-(-4g-4)+4=0

We get rid of parentheses

g+4g+4+4=0

We add all the numbers together, and all the variables

5g+8=0

We move all terms containing g to the left, all other terms to the right

5g=-8

g=-8/5

g=-1+3/5

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