-g+2(3+g)=-4(1g+1

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Solution for -g+2(3+g)=-4(1g+1 equation: 



-g+2(3+g)=-4(1g+1

We move all terms to the left:

-g+2(3+g)-(-4(1g+1)=0

We add all the numbers together, and all the variables

-g+2(g+3)-(-4(g+1)=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(-4(g+1)=0

We multiply parentheses

-1g+2g-(-4(g+1)+6=0

We add all the numbers together, and all the variables

g-(-4(g+1)+6=0

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