-g+2(3+g)=-4(g+)

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Solution for -g+2(3+g)=-4(g+) equation: 



-g+2(3+g)=-4(g+)

We move all terms to the left:

-g+2(3+g)-(-4(g+))=0

We add all the numbers together, and all the variables

-g+2(g+3)-(-4(+g))=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(-4(+g))=0

We multiply parentheses

-1g+2g-(-4(+g))+6=0



We calculate terms in parentheses: -(-4(+g)), so:

-4(+g)

We multiply parentheses

-4g

Back to the equation:

-(-4g)



We add all the numbers together, and all the variables

g-(-4g)+6=0

We get rid of parentheses

g+4g+6=0

We add all the numbers together, and all the variables

5g+6=0

We move all terms containing g to the left, all other terms to the right

5g=-6

g=-6/5

g=-1+1/5

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