-g+2(3+g)=-4(g+1)+10

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Solution for -g+2(3+g)=-4(g+1)+10 equation: 



-g+2(3+g)=-4(g+1)+10

We move all terms to the left:

-g+2(3+g)-(-4(g+1)+10)=0

We add all the numbers together, and all the variables

-g+2(g+3)-(-4(g+1)+10)=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(-4(g+1)+10)=0

We multiply parentheses

-1g+2g-(-4(g+1)+10)+6=0



We calculate terms in parentheses: -(-4(g+1)+10), so:

-4(g+1)+10

We multiply parentheses

-4g-4+10

We add all the numbers together, and all the variables

-4g+6

Back to the equation:

-(-4g+6)



We add all the numbers together, and all the variables

g-(-4g+6)+6=0

We get rid of parentheses

g+4g-6+6=0

We add all the numbers together, and all the variables

5g=0

g=0/5

g=0

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