-g+2(3+g)=-4(g+1)-2

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Solution for -g+2(3+g)=-4(g+1)-2 equation: 



-g+2(3+g)=-4(g+1)-2

We move all terms to the left:

-g+2(3+g)-(-4(g+1)-2)=0

We add all the numbers together, and all the variables

-g+2(g+3)-(-4(g+1)-2)=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(-4(g+1)-2)=0

We multiply parentheses

-1g+2g-(-4(g+1)-2)+6=0



We calculate terms in parentheses: -(-4(g+1)-2), so:

-4(g+1)-2

We multiply parentheses

-4g-4-2

We add all the numbers together, and all the variables

-4g-6

Back to the equation:

-(-4g-6)



We add all the numbers together, and all the variables

g-(-4g-6)+6=0

We get rid of parentheses

g+4g+6+6=0

We add all the numbers together, and all the variables

5g+12=0

We move all terms containing g to the left, all other terms to the right

5g=-12

g=-12/5

g=-2+2/5

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