-g+2(3+g)=5(g+1)

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Solution for -g+2(3+g)=5(g+1) equation:



-g+2(3+g)=5(g+1)
We move all terms to the left:
-g+2(3+g)-(5(g+1))=0
We add all the numbers together, and all the variables
-g+2(g+3)-(5(g+1))=0
We add all the numbers together, and all the variables
-1g+2(g+3)-(5(g+1))=0
We multiply parentheses
-1g+2g-(5(g+1))+6=0
We calculate terms in parentheses: -(5(g+1)), so:
5(g+1)
We multiply parentheses
5g+5
Back to the equation:
-(5g+5)
We add all the numbers together, and all the variables
g-(5g+5)+6=0
We get rid of parentheses
g-5g-5+6=0
We add all the numbers together, and all the variables
-4g+1=0
We move all terms containing g to the left, all other terms to the right
-4g=-1
g=-1/-4
g=1/4

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