-g-2(3+g)=-4(g+1)

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Solution for -g-2(3+g)=-4(g+1) equation: 



-g-2(3+g)=-4(g+1)

We move all terms to the left:

-g-2(3+g)-(-4(g+1))=0

We add all the numbers together, and all the variables

-g-2(g+3)-(-4(g+1))=0

We add all the numbers together, and all the variables

-1g-2(g+3)-(-4(g+1))=0

We multiply parentheses

-1g-2g-(-4(g+1))-6=0



We calculate terms in parentheses: -(-4(g+1)), so:

-4(g+1)

We multiply parentheses

-4g-4

Back to the equation:

-(-4g-4)



We add all the numbers together, and all the variables

-3g-(-4g-4)-6=0

We get rid of parentheses

-3g+4g+4-6=0

We add all the numbers together, and all the variables

g-2=0

We move all terms containing g to the left, all other terms to the right

g=2

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