-i(-15+13i)=0

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Solution for -i(-15+13i)=0 equation:



-i(-15+13i)=0
We add all the numbers together, and all the variables
-i(13i-15)=0
We multiply parentheses
-13i^2+15i=0
a = -13; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-13)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-13}=\frac{-30}{-26} =1+2/13 $
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-13}=\frac{0}{-26} =0 $

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