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-k(-2-3)-(-2)(-k-5)=-2-(-k+4)+3
We move all terms to the left:
-k(-2-3)-(-2)(-k-5)-(-2-(-k+4)+3)=0
We add all the numbers together, and all the variables
-k(-5)-(-2)(-1k-5)-(-2-(-1k+4)+3)=0
We multiply parentheses
5k-(-2)(-1k-5)-(-2-(-1k+4)+3)=0
We multiply parentheses ..
5k-(+2k+10)-(-2-(-1k+4)+3)=0
We calculate terms in parentheses: -(-2-(-1k+4)+3), so:We add all the numbers together, and all the variables
-2-(-1k+4)+3
determiningTheFunctionDomain -(-1k+4)-2+3
We add all the numbers together, and all the variables
-(-1k+4)+1
We get rid of parentheses
1k-4+1
We add all the numbers together, and all the variables
k-3
Back to the equation:
-(k-3)
5k-(2k+10)-(k-3)=0
We get rid of parentheses
5k-2k-k-10+3=0
We add all the numbers together, and all the variables
2k-7=0
We move all terms containing k to the left, all other terms to the right
2k=7
k=7/2
k=3+1/2
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