-k+2/2k+2=-0.25

Solution for -k+2/2k+2=-0.25 equation:

-k+2/2k+2=-0.25

We move all terms to the left:

-k+2/2k+2-(-0.25)=0


Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R


We add all the numbers together, and all the variables

-1k+2/2k+2.25=0

We multiply all the terms by the denominator


-1k*2k+(2.25)*2k+2=0

We multiply parentheses

-1k*2k+4.5k+2=0

Wy multiply elements

-2k^2+4.5k+2=0

a = -2; b = 4.5; c = +2;
Δ = b2-4ac
Δ = 4.52-4·(-2)·2
Δ = 36.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{36.25}}{2*-2}=\frac{-4.5-\sqrt{36.25}}{-4}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{36.25}}{2*-2}=\frac{-4.5+\sqrt{36.25}}{-4}
$