-k-2(k-3)=-6k+9

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Solution for -k-2(k-3)=-6k+9 equation: 



-k-2(k-3)=-6k+9

We move all terms to the left:

-k-2(k-3)-(-6k+9)=0

We add all the numbers together, and all the variables

-1k-2(k-3)-(-6k+9)=0

We multiply parentheses

-1k-2k-(-6k+9)+6=0

We get rid of parentheses

-1k-2k+6k-9+6=0

We add all the numbers together, and all the variables

3k-3=0

We move all terms containing k to the left, all other terms to the right

3k=3

k=3/3

k=1

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