-n+10=2(3n-7)+n

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Solution for -n+10=2(3n-7)+n equation: 



-n+10=2(3n-7)+n

We move all terms to the left:

-n+10-(2(3n-7)+n)=0

We add all the numbers together, and all the variables

-1n-(2(3n-7)+n)+10=0



We calculate terms in parentheses: -(2(3n-7)+n), so:

2(3n-7)+n

We add all the numbers together, and all the variables

n+2(3n-7)

We multiply parentheses

n+6n-14

We add all the numbers together, and all the variables

7n-14

Back to the equation:

-(7n-14)



We get rid of parentheses

-1n-7n+14+10=0

We add all the numbers together, and all the variables

-8n+24=0

We move all terms containing n to the left, all other terms to the right

-8n=-24

n=-24/-8

n=+3

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