-n+2(7-4n)=8(1-2n)+8n

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Solution for -n+2(7-4n)=8(1-2n)+8n equation: 



-n+2(7-4n)=8(1-2n)+8n

We move all terms to the left:

-n+2(7-4n)-(8(1-2n)+8n)=0

We add all the numbers together, and all the variables

-n+2(-4n+7)-(8(-2n+1)+8n)=0

We add all the numbers together, and all the variables

-1n+2(-4n+7)-(8(-2n+1)+8n)=0

We multiply parentheses

-1n-8n-(8(-2n+1)+8n)+14=0



We calculate terms in parentheses: -(8(-2n+1)+8n), so:

8(-2n+1)+8n

We add all the numbers together, and all the variables

8n+8(-2n+1)

We multiply parentheses

8n-16n+8

We add all the numbers together, and all the variables

-8n+8

Back to the equation:

-(-8n+8)



We add all the numbers together, and all the variables

-9n-(-8n+8)+14=0

We get rid of parentheses

-9n+8n-8+14=0

We add all the numbers together, and all the variables

-1n+6=0

We move all terms containing n to the left, all other terms to the right

-n=-6

n=-6/-1

n=+6

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