-n+2(n-1)=2+3n

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Solution for -n+2(n-1)=2+3n equation:



-n+2(n-1)=2+3n
We move all terms to the left:
-n+2(n-1)-(2+3n)=0
We add all the numbers together, and all the variables
-n+2(n-1)-(3n+2)=0
We add all the numbers together, and all the variables
-1n+2(n-1)-(3n+2)=0
We multiply parentheses
-1n+2n-(3n+2)-2=0
We get rid of parentheses
-1n+2n-3n-2-2=0
We add all the numbers together, and all the variables
-2n-4=0
We move all terms containing n to the left, all other terms to the right
-2n=4
n=4/-2
n=-2

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