-n+2=5-(1+2n)

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Solution for -n+2=5-(1+2n) equation: 



-n+2=5-(1+2n)

We move all terms to the left:

-n+2-(5-(1+2n))=0

We add all the numbers together, and all the variables

-n-(5-(2n+1))+2=0

We add all the numbers together, and all the variables

-1n-(5-(2n+1))+2=0



We calculate terms in parentheses: -(5-(2n+1)), so:

5-(2n+1)

determiningTheFunctionDomain
-(2n+1)+5

We get rid of parentheses

-2n-1+5

We add all the numbers together, and all the variables

-2n+4

Back to the equation:

-(-2n+4)



We get rid of parentheses

-1n+2n-4+2=0

We add all the numbers together, and all the variables

n-2=0

We move all terms containing n to the left, all other terms to the right

n=2

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