-n+2=7-(2n-1)

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Solution for -n+2=7-(2n-1) equation: 



-n+2=7-(2n-1)

We move all terms to the left:

-n+2-(7-(2n-1))=0

We add all the numbers together, and all the variables

-1n-(7-(2n-1))+2=0



We calculate terms in parentheses: -(7-(2n-1)), so:

7-(2n-1)

determiningTheFunctionDomain
-(2n-1)+7

We get rid of parentheses

-2n+1+7

We add all the numbers together, and all the variables

-2n+8

Back to the equation:

-(-2n+8)



We get rid of parentheses

-1n+2n-8+2=0

We add all the numbers together, and all the variables

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6

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