-n+4n=2(1+2n)-5(n+6)

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Solution for -n+4n=2(1+2n)-5(n+6) equation: 



-n+4n=2(1+2n)-5(n+6)

We move all terms to the left:

-n+4n-(2(1+2n)-5(n+6))=0

We add all the numbers together, and all the variables

-n+4n-(2(2n+1)-5(n+6))=0

We add all the numbers together, and all the variables

3n-(2(2n+1)-5(n+6))=0



We calculate terms in parentheses: -(2(2n+1)-5(n+6)), so:

2(2n+1)-5(n+6)

We multiply parentheses

4n-5n+2-30

We add all the numbers together, and all the variables

-1n-28

Back to the equation:

-(-1n-28)



We get rid of parentheses

3n+1n+28=0

We add all the numbers together, and all the variables

4n+28=0

We move all terms containing n to the left, all other terms to the right

4n=-28

n=-28/4

n=-7

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