-n-6(1-2n)=8(2+n)+n

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Solution for -n-6(1-2n)=8(2+n)+n equation: 



-n-6(1-2n)=8(2+n)+n

We move all terms to the left:

-n-6(1-2n)-(8(2+n)+n)=0

We add all the numbers together, and all the variables

-n-6(-2n+1)-(8(n+2)+n)=0

We add all the numbers together, and all the variables

-1n-6(-2n+1)-(8(n+2)+n)=0

We multiply parentheses

-1n+12n-(8(n+2)+n)-6=0



We calculate terms in parentheses: -(8(n+2)+n), so:

8(n+2)+n

We add all the numbers together, and all the variables

n+8(n+2)

We multiply parentheses

n+8n+16

We add all the numbers together, and all the variables

9n+16

Back to the equation:

-(9n+16)



We add all the numbers together, and all the variables

11n-(9n+16)-6=0

We get rid of parentheses

11n-9n-16-6=0

We add all the numbers together, and all the variables

2n-22=0

We move all terms containing n to the left, all other terms to the right

2n=22

n=22/2

n=11

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