-n2+2n+4=5

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Solution for -n2+2n+4=5 equation: 



-n2+2n+4=5

We move all terms to the left:

-n2+2n+4-(5)=0

We add all the numbers together, and all the variables

-1n^2+2n-1=0

a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-2}{-2}=1$

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