-n2-n+3000=0

Solution for -n2-n+3000=0 equation:

-n2-n+3000=0

We add all the numbers together, and all the variables

-1n^2-1n+3000=0

a = -1; b = -1; c = +3000;
Δ = b2-4ac
Δ = -12-4·(-1)·3000
Δ = 12001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{12001}}{2*-1}=\frac{1-\sqrt{12001}}{-2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{12001}}{2*-1}=\frac{1+\sqrt{12001}}{-2}
$