-p-4-(2p-5)=4+2(p-3)

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Solution for -p-4-(2p-5)=4+2(p-3) equation:



-p-4-(2p-5)=4+2(p-3)
We move all terms to the left:
-p-4-(2p-5)-(4+2(p-3))=0
We add all the numbers together, and all the variables
-1p-(2p-5)-(4+2(p-3))-4=0
We get rid of parentheses
-1p-2p-(4+2(p-3))+5-4=0
We calculate terms in parentheses: -(4+2(p-3)), so:
4+2(p-3)
determiningTheFunctionDomain 2(p-3)+4
We multiply parentheses
2p-6+4
We add all the numbers together, and all the variables
2p-2
Back to the equation:
-(2p-2)
We add all the numbers together, and all the variables
-3p-(2p-2)+1=0
We get rid of parentheses
-3p-2p+2+1=0
We add all the numbers together, and all the variables
-5p+3=0
We move all terms containing p to the left, all other terms to the right
-5p=-3
p=-3/-5
p=3/5

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