-q/3+12=2

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Solution for -q/3+12=2 equation: 



-q/3+12=2

We move all terms to the left:

-q/3+12-(2)=0

We add all the numbers together, and all the variables

-q/3+10=0

We multiply all the terms by the denominator


-q+10*3=0

We add all the numbers together, and all the variables

-1q+30=0

We move all terms containing q to the left, all other terms to the right

-q=-30

q=-30/-1

q=+30

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