-r-2(r+5)=8(r+7)

Solution for -r-2(r+5)=8(r+7) equation:

-r-2(r+5)=8(r+7)

We move all terms to the left:

-r-2(r+5)-(8(r+7))=0

We add all the numbers together, and all the variables

-1r-2(r+5)-(8(r+7))=0

We multiply parentheses

-1r-2r-(8(r+7))-10=0


We calculate terms in parentheses: -(8(r+7)), so:

8(r+7)

We multiply parentheses

8r+56

Back to the equation:

-(8r+56)


We add all the numbers together, and all the variables

-3r-(8r+56)-10=0

We get rid of parentheses

-3r-8r-56-10=0

We add all the numbers together, and all the variables

-11r-66=0

We move all terms containing r to the left, all other terms to the right

-11r=66

r=66/-11

r=-6