-r2+6r-5=3r2+3r-2

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Solution for -r2+6r-5=3r2+3r-2 equation: 



-r2+6r-5=3r^2+3r-2

We move all terms to the left:

-r2+6r-5-(3r^2+3r-2)=0

We add all the numbers together, and all the variables

-1r^2+6r-(3r^2+3r-2)-5=0

We get rid of parentheses

-1r^2-3r^2+6r-3r+2-5=0

We add all the numbers together, and all the variables

-4r^2+3r-3=0

a = -4; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-4)·(-3)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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